Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:39Z
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
276K
F = ma
10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}