Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 14:03Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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e^{i\pi} + 1 = 0
det| 10 9 ; 0 11 | = 110
129K
2H₂ + O₂ → 2H₂O
det| 7 4 ; 4 8 | = 40
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
153K
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-β²) dβ = √π / 2
∫₀^∞ e^(-t²) dt = √π / 2