Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:24Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
det| 9 4 ; 1 10 | = 86
198K
6φ² + 8φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
63K
∂φ/∂φ = 1φ
CH₄ + 2O₂ → CO₂ + 2H₂O
201K
det| 4 8 ; 1 5 | = 12
det| 1 4 ; 3 2 | = -10
319K
∫₀^∞ e^(-ψ²) dψ = √π / 2
359K