Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 00:38Z
12r² + 5r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
iħ ∂ψ/∂t = Ĥψ
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
155K
det| 7 4 ; 4 8 | = 40
63K
11x² + 6x + 2 = 0
det| 1 4 ; 3 2 | = -10
366K
∑_{k=1}^{n} k = n(n+1)/2
319K