Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 15:54Z
\lim_{y\to 0} \frac{\sin y}{y} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\lim_{β\to 0} \frac{\sin β}{β} = 1
155K
det| 8 8 ; 0 9 | = 72
det| 10 4 ; 1 11 | = 106
201K
λ = h/p
AgNO₃ + NaCl → AgCl↓ + NaNO₃