Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:47Z
2ψ² + 5ψ + 4 = 0
∫₀^∞ e^(-z²) dz = √π / 2
479K
N₂ + 3H₂ ⇌ 2NH₃
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
191K
det| 5 6 ; 7 6 | = -12
390K
∇²z = 0
det| 11 5 ; 0 12 | = 132
1K
det| 9 4 ; 1 10 | = 86
153K
det| 3 7 ; 2 4 | = -2
338K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
188K
det| 7 9 ; 1 8 | = 47
416K