Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:26Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
12β² + 9β + 3 = 0
det| 3 7 ; 2 4 | = -2
129K
∂z/∂n = 8z
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-ψ²) dψ = √π / 2
4γ² + 9γ + 7 = 0