Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:42Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
75K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-ψ²) dψ = √π / 2
276K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 7 4 ; 4 8 | = 40
191K
∇²z = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-x²) dx = √π / 2
338K
8t² + 2t + 3 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
188K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1