Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:40Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
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\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 12 1 ; 1 13 | = 155
\lim_{t\to 0} \frac{\sin t}{t} = 1
N₂ + 3H₂ ⇌ 2NH₃