Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:35Z
∇²α = 0
6φ² + 8φ + 4 = 0
det| 7 6 ; 1 8 | = 50
155K
∫₀^∞ e^(-φ²) dφ = √π / 2
63K
∂φ/∂φ = 1φ
det| 4 8 ; 1 5 | = 12
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0