Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:21Z
∑_{k=1}^{n} k = n(n+1)/2
det| 3 3 ; 4 4 | = 0
479K
3β² + 6β + 2 = 0
det| 10 2 ; 1 11 | = 108
129K
F = ma
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 9 ; 0 6 | = 30
473K
det| 1 4 ; 3 2 | = -10
416K