Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:32Z
∇ × E = −∂B/∂t
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
276K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
129K
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
390K
10n² + 4n + 5 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
473K
∑_{k=1}^{n} k = n(n+1)/2
338K
d/dy [y^11] = 11y^10
188K