Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:21Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
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∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
det| 11 9 ; 0 12 | = 132
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-x²) dx = √π / 2
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