Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 05:50Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
326K
11y² + 4y + 3 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
155K
d/dy [y^6] = 6y^5
det| 5 6 ; 2 6 | = 18
201K
8ω² + 6ω + 2 = 0
det| 7 4 ; 4 8 | = 40
319K
\frac{4}{2} \sum_{i=1}^{n} i^{2}