Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:44Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-x²) dx = √π / 2
276K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∇²z = 0
∑_{k=1}^{n} k = n(n+1)/2
153K
N₂ + 3H₂ ⇌ 2NH₃
det| 5 2 ; 3 6 | = 24
473K
8t² + 2t + 3 = 0
det| 7 2 ; 7 8 | = 42
188K
det| 4 8 ; 3 5 | = -4
416K
F = ma
∫₀^∞ e^(-φ²) dφ = √π / 2