Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:20Z
∑_{k=1}^{n} k = n(n+1)/2
det| 12 1 ; 4 13 | = 152
75K
3β² + 6β + 2 = 0
det| 11 5 ; 0 12 | = 132
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
473K
∇²ψ = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃