Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
479K
11n² + 1n + 0 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 10 2 ; 1 11 | = 108
390K
4y² + 8y + 1 = 0
det| 11 7 ; 4 12 | = 104
CH₄ + 2O₂ → CO₂ + 2H₂O
338K
∑_{k=1}^{n} k = n(n+1)/2
det| 7 6 ; 1 8 | = 50
188K
det| 5 2 ; 2 6 | = 26