Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:07Z
11t² + 7t + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
198K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 7 4 ; 4 8 | = 40
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-φ²) dφ = √π / 2
359K