Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:04Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
479K
12β² + 9β + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
∂z/∂n = 8z
e^{i\pi} + 1 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
1K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
2H₂ + O₂ → 2H₂O
det| 7 4 ; 4 8 | = 40
188K
4γ² + 9γ + 7 = 0