Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:48Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
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\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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det| 11 9 ; 0 12 | = 132
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∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
d/dy [y^11] = 11y^10
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det| 7 4 ; 4 8 | = 40
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