Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:35Z
det| 4 5 ; 4 5 | = 0
det| 7 4 ; 4 8 | = 40
75K
det| 5 9 ; 7 6 | = -33
479K
N₂ + 3H₂ ⇌ 2NH₃
det| 4 4 ; 5 5 | = 0
276K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
∑_{k=1}^{n} k = n(n+1)/2
1K
CH₄ + 2O₂ → CO₂ + 2H₂O
473K