Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
\frac{12}{6} \sum_{i=1}^{n} i^{2}
276K
∫₀^∞ e^(-n²) dn = √π / 2
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0
∇²ψ = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
3φ² + 8φ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}