Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:29Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
75K
det| 11 5 ; 0 12 | = 132
479K
3β² + 6β + 2 = 0
F = ma
det| 6 6 ; 3 7 | = 24
191K
∑_{k=1}^{n} k = n(n+1)/2
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
473K
∇²ψ = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
416K
3φ² + 8φ + 6 = 0