Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:49Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
326K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
198K
7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
201K
det| 10 9 ; 3 11 | = 83
det| 9 4 ; 1 10 | = 86
176K
det| 10 7 ; 3 11 | = 89
319K
2ψ² + 6ψ + 0 = 0
ω = 2πf
∂ψ/∂t = 3ψ
6θ² + 3θ + 6 = 0