Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
129K
F = ma
det| 12 1 ; 4 13 | = 152
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
1x² + 5x + 7 = 0
det| 3 7 ; 2 4 | = -2
473K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
338K
∇²ψ = 0