Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:55Z
7φ² + 4φ + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
e^{i\pi} + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
176K
det| 11 4 ; 5 12 | = 112
319K
det| 6 6 ; 3 7 | = 24
359K
det| 7 4 ; 4 8 | = 40
233K
det| 1 4 ; 3 2 | = -10
412K