Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:03Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
F = ma
det| 7 4 ; 4 8 | = 40
191K
det| 3 7 ; 2 4 | = -2
153K
CH₄ + 2O₂ → CO₂ + 2H₂O
473K
det| 4 4 ; 5 5 | = 0
338K