Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:22Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
det| 4 8 ; 3 5 | = -4
129K
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
191K
det| 9 4 ; 1 10 | = 86
390K
∫₀^∞ e^(-φ²) dφ = √π / 2
153K