Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 14:23Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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det| 3 3 ; 4 4 | = 0
479K
e^{i\pi} + 1 = 0
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
191K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
338K
∫₀^∞ e^(-β²) dβ = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
188K
∫₀^∞ e^(-t²) dt = √π / 2