Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 15:36Z
d/dz [z^3] = 3z^2
6φ² + 8φ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
ω = 2πf
∫₀^∞ e^(-n²) dn = √π / 2
390K
det| 10 8 ; 7 11 | = 54
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 4 6 ; 4 5 | = -4
153K
det| 5 6 ; 2 6 | = 18
det| 9 4 ; 1 10 | = 86
473K
∑_{k=1}^{n} k = n(n+1)/2
338K
d/dy [y^11] = 11y^10
188K