Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:37Z
11t² + 7t + 4 = 0
det| 3 7 ; 2 4 | = -2
326K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 1 4 ; 0 2 | = 2
359K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
263K