Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:10Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
11n² + 1n + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
4y² + 8y + 1 = 0
det| 11 7 ; 4 12 | = 104
det| 4 6 ; 4 5 | = -4
473K
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf
det| 5 2 ; 2 6 | = 26
e^{i\pi} + 1 = 0