Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:39Z
det| 3 3 ; 5 4 | = -3
det| 10 7 ; 3 11 | = 89
75K
∇²β = 0
det| 11 4 ; 5 12 | = 112
129K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
191K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
1K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 11 9 ; 5 12 | = 87
473K
E = mc²
det| 3 7 ; 2 4 | = -2
det| 8 5 ; 1 9 | = 67
∂t/∂β = 2t
PV = nRT