Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:44Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
N₂ + 3H₂ ⇌ 2NH₃
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
276K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-ψ²) dψ = √π / 2
390K
∇²z = 0
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 3 1 ; 7 4 | = 5
153K
N₂ + 3H₂ ⇌ 2NH₃
det| 7 9 ; 1 8 | = 47
473K
det| 9 4 ; 1 10 | = 86
338K
8t² + 2t + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
188K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1