Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:35Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
∫₀^∞ e^(-φ²) dφ = √π / 2
479K
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
153K