Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:56Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 5 2 ; 3 6 | = 24
276K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
∑_{k=1}^{n} k = n(n+1)/2
153K
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 7 4 ; 4 8 | = 40
338K
det| 8 9 ; 4 9 | = 36
188K