Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:38Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
390K
∑_{k=1}^{n} k = n(n+1)/2
153K
CH₄ + 2O₂ → CO₂ + 2H₂O
473K