Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:17Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
∫₀^∞ e^(-n²) dn = √π / 2
129K
F = ma
det| 1 4 ; 3 2 | = -10
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 6 ; 7 6 | = -12
1K
det| 4 8 ; 3 5 | = -4
153K
1x² + 5x + 7 = 0
det| 7 9 ; 1 8 | = 47
473K
∇²ψ = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
188K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
3φ² + 8φ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}