Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 15:40Z
d/dz [z^3] = 3z^2
∑_{k=1}^{n} k = n(n+1)/2
479K
6φ² + 8φ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
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ω = 2πf
det| 9 4 ; 1 10 | = 86
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det| 10 8 ; 7 11 | = 54
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 5 6 ; 2 6 | = 18
338K