Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:39Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
326K
det| 10 7 ; 4 11 | = 82
∫₀^∞ e^(-x²) dx = √π / 2
155K
∫₀^∞ e^(-φ²) dφ = √π / 2
63K
λ = h/p
4θ² + 9θ + 6 = 0
det| 3 7 ; 2 4 | = -2
319K
det| 8 5 ; 5 9 | = 47
\frac{1}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dx [x^12] = 12x^11
3n² + 5n + 4 = 0