Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:15Z
11t² + 7t + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-φ²) dφ = √π / 2
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det| 5 9 ; 0 6 | = 30
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det| 9 4 ; 1 10 | = 86
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∫₀^∞ e^(-t²) dt = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
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det| 11 5 ; 0 12 | = 132
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