Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:43Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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det| 10 7 ; 4 11 | = 82
\lim_{β\to 0} \frac{\sin β}{β} = 1
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λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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4θ² + 9θ + 6 = 0
det| 7 4 ; 4 8 | = 40
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det| 8 5 ; 5 9 | = 47
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dx [x^12] = 12x^11
3n² + 5n + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0