Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:39Z
∑_{k=1}^{n} k = n(n+1)/2
det| 8 6 ; 6 9 | = 36
75K
8β² + 2β + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
276K
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 1 4 ; 3 2 | = -10
153K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
188K
∑_{k=1}^{n} k = n(n+1)/2
416K