Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:23Z
11t² + 7t + 4 = 0
E = mc²
det| 1 4 ; 3 2 | = -10
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
359K
ΔS ≥ 0