Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 05:00Z
∑_{k=1}^{n} k = n(n+1)/2
11y² + 4y + 3 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
63K
d/dy [y^6] = 6y^5
\frac{2}{2} \sum_{i=1}^{n} i^{2}
201K
8ω² + 6ω + 2 = 0
det| 9 4 ; 1 10 | = 86
319K
\frac{4}{2} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
359K
λ = h/p
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 6 7 ; 3 7 | = 21
3x² + 3x + 5 = 0