Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:08Z
11t² + 7t + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
198K
E = mc²
det| 10 7 ; 3 11 | = 89
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-t²) dt = √π / 2
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-ψ²) dψ = √π / 2
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 10 1 ; 4 11 | = 106
\binom{n}{k} = \frac{n!}{k!(n-k)!}
412K
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ