Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 14:30Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
276K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
1K
det| 12 1 ; 4 13 | = 152
153K
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-β²) dβ = √π / 2