Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:56Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
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3β² + 6β + 2 = 0
det| 12 1 ; 4 13 | = 152
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∑_{k=1}^{n} k = n(n+1)/2
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F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-φ²) dφ = √π / 2
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