Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:24Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12β² + 9β + 3 = 0
det| 3 7 ; 2 4 | = -2
129K
∂z/∂n = 8z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
191K
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
e^{i\pi} + 1 = 0