Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:46Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
326K
7r² + 8r + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
63K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 9 4 ; 1 10 | = 86
201K
det| 10 9 ; 3 11 | = 83
2ψ² + 6ψ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
359K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
263K
ω = 2πf